first, with working snowflakes.c but it doesn't pass the time limit, it's brute force.
This commit is contained in:
1
README.md
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1
README.md
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This repo is to document my progress working through the book "Algorithmic Thinking".
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30
food_line.c
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30
food_line.c
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#include <stdio.h>
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#define MAX_LINES 100
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int main()
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{
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int i, j, num_lines, num_new_people;
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int lines[MAX_LINES];
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scanf("%d%d", &num_lines, &num_new_people);
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for (i = 0; i < num_lines; i++)
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{
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scanf("%d", &lines[i]);
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}
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int smallest;
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int smallest_index = -1;
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for (i = 0; i < num_new_people; i++)
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{
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smallest = 101;
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for (j = 0; j < num_lines; j++)
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{
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if (lines[j] < smallest) {
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smallest = lines[j];
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smallest_index = j;
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}
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}
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printf("%d\n", smallest);
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lines[smallest_index] += 1;
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}
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return 0;
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}
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6
snowflakes/Makefile
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snowflakes/Makefile
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build:
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clang snowflakes.c -o snowflakes
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run:
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./snowflakes < snowflakes.txt
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go:
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clang snowflakes.c -o snowflakes && ./snowflakes < snowflakes.txt
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#include <stdio.h>
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typedef struct Node
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{
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int value;
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struct Node * next;
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} Node;
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int main()
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{
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Node nodes[5];
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for (int i = 0; i < 5; i++)
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{
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nodes[i].value = i + 42;
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if (i > 0)
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{
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nodes[i - 1].next = &nodes[i];
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}
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}
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for (int i = 0; i < 5; i++)
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{
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printf("node at %d has value %d\n", i, nodes[i].value);
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if (i > 0)
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{
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printf("node at %d has value %d\n", i - 1, nodes[i - 1].value);
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printf(
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"that node's 'next' is %p and, as expected, its 'next' has value %d\n",
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nodes[i - 1].next, nodes[i - 1].next->value
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);
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}
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}
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return 0;
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}
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#include <stdlib.h>
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#include <stdio.h>
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typedef struct Node
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{
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int value;
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struct Node * next;
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} Node;
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int main(void)
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{
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Node nodes[5];
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for (int i = 0; i < 5; i++)
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{
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Node curr_node = { i };
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nodes[i] = curr_node;
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printf("Node in ARR current after insertion: %d\n", nodes[i].value);
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printf("Node _address_ in ARR current after insertion: %p\n", &nodes[i]);
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}
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for (int i = 0; i < 5; i++)
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{
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printf("Node in ARR: %d\n", nodes[i].value);
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}
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return 0;
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}
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#include <stdlib.h>
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#include <stdio.h>
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typedef struct Node
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{
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int value;
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struct Node * next;
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} Node;
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int main(void)
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{
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Node *nodes[5];
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for (int i = 0; i < 5; i++)
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{
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Node * curr_node = malloc(sizeof(Node));
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curr_node->value = i;
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nodes[i] = curr_node;
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printf("Node in ARR current after insertion: %d\n", nodes[i]->value);
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printf("Node _address_ in ARR current after insertion: %p\n", &nodes[i]);
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}
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for (int i = 0; i < 5; i++)
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{
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printf("Node in ARR: %d\n", nodes[i]->value);
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}
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return 0;
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}
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#include <stdio.h>
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#include <stdlib.h>
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#define ARRAY_LEN 1047505
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typedef struct Node
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{
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int value;
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struct Node * next;
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} Node;
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Node * make_node(int value)
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{
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Node * node = malloc(sizeof(Node));
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node->value = value;
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return node;
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}
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int main()
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{
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Node * nodes[ARRAY_LEN];
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for (int i = 0; i < ARRAY_LEN; i++)
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{
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nodes[i] = make_node(i);
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}
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for (int i = 0; i < ARRAY_LEN; i++)
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{
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printf("Node in ARR: %d\n", nodes[i]->value);
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}
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return 0;
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}
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BIN
snowflakes/snowflakes
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BIN
snowflakes/snowflakes
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Binary file not shown.
87
snowflakes/snowflakes.c
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87
snowflakes/snowflakes.c
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#include <stdio.h>
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#include <stdbool.h>
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#define STRING_THERE_ARE_DUPLICATE_SNOWFLAKES "Twin snowflakes found.\n"
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#define STRING_SNOWFLAKES_ARE_UNIQUE "No two snowflakes are alike.\n"
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#define LEN_SNOWFLAKE 6
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int get_num_snowflakes_from_stdin(void)
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{
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int num_snowflakes;
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scanf("%d", &num_snowflakes);
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return num_snowflakes;
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}
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bool they_are_equal_right(int sf1[LEN_SNOWFLAKE], int sf2[LEN_SNOWFLAKE], int sf2_offset)
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{
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int sf1_tip, sf2_tip, sf2_index;
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for (int i = 0; i < LEN_SNOWFLAKE; i++)
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{
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sf1_tip = sf1[i];
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sf2_index = (i + sf2_offset) % LEN_SNOWFLAKE;
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sf2_tip = sf2[sf2_index];
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if (sf1_tip != sf2_tip)
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return false;
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}
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return true;
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}
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bool they_are_equal_left(int sf1[LEN_SNOWFLAKE], int sf2[LEN_SNOWFLAKE], int sf2_offset)
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{
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int sf1_tip, sf2_tip, sf2_index;
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for (int i = 0; i < LEN_SNOWFLAKE; i++)
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{
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sf1_tip = sf1[i];
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sf2_index = sf2_offset - i;
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if (sf2_index < 0)
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sf2_index = sf2_index + LEN_SNOWFLAKE;
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sf2_tip = sf2[sf2_index];
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if (sf1_tip != sf2_tip)
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return false;
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}
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return true;
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}
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bool they_are_equal(int sf1[LEN_SNOWFLAKE], int sf2[LEN_SNOWFLAKE])
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{
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for (int o = 0; o < LEN_SNOWFLAKE; o++)
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{
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if (they_are_equal_right(sf1, sf2, o))
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return true;
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if (they_are_equal_left(sf1, sf2, o))
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return true;
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}
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return false;
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}
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void populate_snowflakes_from_stdin(int snowflakes[][LEN_SNOWFLAKE], int num_snowflakes)
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{
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for (int i = 0; i < num_snowflakes; i++)
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for (int j = 0; j < LEN_SNOWFLAKE; j++)
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scanf("%d", &snowflakes[i][j]);
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}
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int main(void)
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{
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// TODO: refactor to only compare similar snowflakes:
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// - the tips add up to the same amount
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// - try to skip any array (hash map) slots with one or fewer elements stored
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int num_snowflakes = get_num_snowflakes_from_stdin();
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int snowflakes[num_snowflakes][LEN_SNOWFLAKE];
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populate_snowflakes_from_stdin(snowflakes, num_snowflakes);
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for (int i = 0; i < num_snowflakes; i++)
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for (int j = i + 1; j < num_snowflakes; j++)
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if (they_are_equal(snowflakes[i], snowflakes[j]))
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{
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printf(STRING_THERE_ARE_DUPLICATE_SNOWFLAKES);
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return 0;
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}
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printf(STRING_SNOWFLAKES_ARE_UNIQUE);
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return 0;
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}
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25
snowflakes/snowflakes.md
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25
snowflakes/snowflakes.md
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Two snowflakes are identical if they are the same,
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if we can make them the same by moving rightward
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through one of the snowflakes (moving clockwise),
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or if we can make them the same by moving leftward
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through one of the snowflakes (moving counterclockwise).
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# Input
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The first line of input is an integer n,
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the number of snowflakes that we’ll be processing.
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The value n will be between 1 and 100,000.
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Each of the following n lines represents one snowflake:
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each line has six integers, where each integer is
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at least 0 and at most 10,000,000.
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# Output
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Our output will be a single line of text:
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If there are no identical snowflakes, output exactly
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"No two snowflakes are alike."
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If there are at least two identical snowflakes, output exactly
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"Twin snowflakes found."
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The time limit for solving the test cases is one second.
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6
snowflakes/snowflakes.txt
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6
snowflakes/snowflakes.txt
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4
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6 5 4 3 2 1
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15 12 12 12 12 12
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4 5 6 1 2 3
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1 1 1 1 1 1
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